Leviackermanscumdropidn
Answered

Discover a wealth of information and get your questions answered on IDNLearn.com. Get timely and accurate answers to your questions from our dedicated community of experts who are here to help you.

Solid strontium chromate, SrCrO4, dissolves into its respective ions at 25°C. Suppose that in a particular solution, [Sr^2+]=6.0x10^-3M. Find the value of Ksp.
A) 3.6 x 10^-5
B) 6.0 x 10^-3
C) 3.6 x 10^-2
D) 7.7 x 10^-2

Sagot :

Sebassandinidn

Answer:

A) 3.6 x 10^-5.

Explanation:

Hello there!

In this case, according to the given information, it turns out firstly necessary to write the equilibrium expression for the dissociation of strontium chromate:

[tex]Ksp=[Sr^{2+}][CrO_4^{2-}][/tex]

Thus, since strontium and chromate ions are in a 1:1 mole ratio, we can tell the concentration of both ions as the same; and therefore, the Ksp is:

[tex]Ksp=(6.0x10^{-3}M)(6.0x10^{-3}M)\\\\Ksp=3.6x10^{-5}[/tex]

Or option A) 3.6 x 10^-5.

Regards!

We are happy to have you as part of our community. Keep asking, answering, and sharing your insights. Together, we can create a valuable knowledge resource. Thank you for choosing IDNLearn.com. We’re committed to providing accurate answers, so visit us again soon.