Leviackermanscumdropidn
Answered

Uncover valuable information and solutions with IDNLearn.com's extensive Q&A platform. Ask your questions and get detailed, reliable answers from our community of experienced experts.

Solid strontium chromate, SrCrO4, dissolves into its respective ions at 25°C. Suppose that in a particular solution, [Sr^2+]=6.0x10^-3M. Find the value of Ksp.
A) 3.6 x 10^-5
B) 6.0 x 10^-3
C) 3.6 x 10^-2
D) 7.7 x 10^-2

Sagot :

Sebassandinidn

Answer:

A) 3.6 x 10^-5.

Explanation:

Hello there!

In this case, according to the given information, it turns out firstly necessary to write the equilibrium expression for the dissociation of strontium chromate:

[tex]Ksp=[Sr^{2+}][CrO_4^{2-}][/tex]

Thus, since strontium and chromate ions are in a 1:1 mole ratio, we can tell the concentration of both ions as the same; and therefore, the Ksp is:

[tex]Ksp=(6.0x10^{-3}M)(6.0x10^{-3}M)\\\\Ksp=3.6x10^{-5}[/tex]

Or option A) 3.6 x 10^-5.

Regards!

We appreciate your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. Thank you for choosing IDNLearn.com for your queries. We’re committed to providing accurate answers, so visit us again soon.