[tex]\huge\bold{To\:find :}[/tex]
The value of [tex]x°[/tex].
[tex]\large\mathfrak{{\pmb{\underline{\orange{Solution}}{\orange{:}}}}}[/tex]
The value of [tex]x°[/tex] is 150°. ✅
[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]
We know that,
[tex]\sf\purple{Sum\:of\:angles\:on\:a\:straight\:line\:= \:180°}[/tex]
➡ 81° + [tex]y°[/tex] = 180°
➡ [tex]y°[/tex] = 180° -81°
➡ [tex]y°[/tex] = 99°
Since an exterior angle of a triangle is equal to the sum of the two opposite interior angles, we have
[tex]x°[/tex] = [tex]y°[/tex] + 51°
Substituting the value of ''[tex]y°[/tex]" in the above equation,
➪ [tex]x°[/tex] = 99° + 51°
➪ [tex]x°[/tex] = 150°
[tex]\sf\red{Therefore, \:the\: value \:of \:x°\: is \:150°.}[/tex]
Note:-
Kindly refer to the attached file.
[tex]{\boxed{\mathcal{\blue{Happy\:learning .}}}}[/tex]
