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help with khan academy problem, law of sines

Help With Khan Academy Problem Law Of Sines class=

Sagot :

Answer:

104°

Step-by-step explanation:

[tex]\frac{sin~B}{18} =\frac{sin~29}{9} \\sin~B=\frac{18}{9} \times sin~29\\sin~B=2~sin~29\\B=sin^{-1}(2 ~sin~29)\\=104^\circ[/tex]

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