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khan academy, law of sines

Khan Academy Law Of Sines class=

Sagot :

SDCInfinityidn

Answer:

m∠B = 76°

Step-by-step explanation:

[tex]\frac{sinB}{b}=\frac{sinC}{c}\\\\sinB=\frac{sinC}{c}(b)\\\\B=sin^{-1}(\frac{sin(29)}{9}(18))\\\\B=75.8=76[/tex]

Therefore, m∠B = 76°.

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