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find the equation of the line that is perpendicluar to y=-2/3x and contains the point (4,-8)

Sagot :

Jcherry99idn

Answer:

Step-by-step explanation:

The slope of two perpendiculars is

m1*m2 = - 1

m1 = - 2/3

-2/3 * m2 = -1                      Multiply both sides by -3/2

-3/2 * -2/3 * m2 = -1*-3/2

m2 = 3/2

So far what you have is

y = 3/2 x + b

x = 4

y = - 8

-8 = 3/2*4 + b

-8 = 6 + b           Subtract 6 from both sides

b = - 14

Complete line

y = 3/2 x  - 14

The red line is y = -2/3x

The blue line is y = 3/2x - 14

The point (4,-8) is marked for you

View image Jcherry99
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