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if (a/b) =(9/7)^-3 ÷(3/7)^1, then find the value of (a/b)^2​

Sagot :

Answer:

decimal = 1.20527

Step-by-step explanation:

[tex]\frac{a}{b} = (\frac{9}{7})^{-3} \div (\frac{3}{7})^1[/tex]

  [tex]=(\frac{7}{9})^3 \times \frac{7}{3}\\\\[/tex]

[tex](\frac{a}{b})^2 = ((\frac{7}{9})^3)^2 \times (\frac{7}{3})^2\\\\[/tex]

      [tex]= \frac{7^6 \times 7^2}{9^6 \times 3^2}\\\\= \frac{7^8}{9^6 \times 9}\\\\=\frac{7^8}{9^7}\\\\=\frac{7^7 \times 7}{9^7}\\\\= 7 \times \frac{7^7}{9^7}\\\\= 7 \times (\frac{7}{9})^7[/tex]

      [tex]=\frac{5764801}{4782969}[/tex]