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John, Jack, Jim, and Joe all decided to take up horseback riding. Jim went twice as many times as Jack, and John went four more times than Joe but three less times than Jim. Joe went 15 times altogether. How many times did Jack go?

Sagot :

MrRoyalidn

Answer:

11 times

Step-by-step explanation:

Given

[tex]Jim = 2 * Jack[/tex]

[tex]John = 4 + Joe[/tex]

[tex]John = Jim - 3[/tex]

[tex]Joe = 15[/tex]

Required

Find [tex]Jack[/tex]

Substitute [tex]Joe = 15[/tex] in [tex]John = 4 + Joe[/tex]

[tex]John = 4 + 15[/tex]

[tex]John = 19[/tex]

Substitute [tex]John = 19[/tex] in [tex]John = Jim - 3[/tex]

[tex]19 = Jim - 3[/tex]

Collect like terms

[tex]Jim = 19 +3[/tex]

[tex]Jim = 22[/tex]

Substitute [tex]Jim = 22[/tex] in [tex]Jim = 2 * Jack[/tex]

[tex]22 = 2 * Jack[/tex]

Divide both sides by 2

[tex]Jack = \frac{22}{2}[/tex]

[tex]Jack = 11[/tex]

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