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Answer:
a. i. sinθ = +0.941
ii. cosθ = +0.339
b. i. sinθ = -0.842
ii. cosθ = +0.540
Step-by-step explanation:
a. Given that tanθ almost equal to≈ 2.773 where 0<θ<π/2, find the values of sinθ and cosθ.
i. sinθ
Given that 1 + cot²θ = cosec²θ
cotθ = 1/tanθ
Since tanθ = 2.773, cotθ = 1/tanθ = 1/2.773 = 0.3606
So, 1 + cot²θ = cosec²θ
1 + (0.3606)² = cosec²θ
1 + 0.13 = cosec²θ
1.13 = cosec²θ
cosec²θ = 1.13
cosecθ = ±√1.13
cosecθ = ±1.063
1/sinθ = ±1.063
sinθ = ±1/1.063
sinθ = ±0.9407
sinθ ≅ ±0.941
Since we have 0<θ<π/2, sinθ is in the first quadrant, so we choose the positive value.
So, sinθ = +0.941 where 0<θ<π/2
ii. cosθ
Given that 1 + tan²θ = sec²θ
Since tanθ = 2.773,
So, 1 + tan²θ = sec²θ
1 + (2.773)² = sec²θ
1 + 7.6895 = sec²θ
8.6895 = sec²θ
sec²θ = 8.6895
secθ = ±√8.6895
secθ = ±2.9478
1/cosθ = ±2.9478
cosθ = ±1/2.9478
cosθ = ±0.3392
cosθ ≈ ±0.339
Since we have 0<θ<π/2, cosθ is in the first quadrant, so we choose the positive value.
So, cosθ = +0.339 where 0<θ<π/2
b. Given that tanθ ≈ -1.559 where 3π/2<θ<2π, find the values of sinθ and cosθ.
i. sinθ
Given that 1 + cot²θ = cosec²θ
cotθ = 1/tanθ
Since tanθ = -1.559, cotθ = 1/tanθ = 1/-1.559 = -0.6414
So, 1 + cot²θ = cosec²θ
1 + (-0.6414)² = cosec²θ
1 + 0.4114 = cosec²θ
1.4114 = cosec²θ
cosec²θ = 1.4114
cosecθ = ±√1.4114
cosecθ = ±1.1880
1/sinθ = ±1.1880
sinθ = ±1/1.1880
sinθ = ±0.8417
sinθ ≈ ±0.842
Since we have 3π/2<θ<2π, sinθ is in the fourth quadrant, so we choose the negative value.
So, sinθ = -0.842 where 3π/2<θ<2π
ii. cosθ
Given that 1 + tan²θ = sec²θ
Since tanθ = -1.559,
So, 1 + tan²θ = sec²θ
1 + (-1.559)² = sec²θ
1 + 2.4305 = sec²θ
3.4305 = sec²θ
sec²θ = 3.4305
secθ = ±√3.4305
secθ = ±1.8522
1/cosθ = ±1.8522
cosθ = ±1/1.8522
cosθ = ±0.5399
cosθ ≈ ±0.540
Since we have 3π/2<θ<2π, cosθ is in the fourth quadrant, so we choose the positive value.
So, cosθ = +0.540 where 3π/2<θ<2π