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Write the log equation as an exponential equation. You do not need to solve for x. \log_9\left(2\right)=2x-1 log 9 ​ (2)=2x−1

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Answer:

[tex]9^{2x-1} = 2\\[/tex]

Step-by-step explanation:

According to the law of logarithm;

[tex]If \ log_ab = x\\a^x = b[/tex]

Given

[tex]\log_9\left(2\right)=2x-1[/tex]

Comparing with the original expression;

a = 9, b = 2 and c = 2x - 1

Substitute into the result indicinal expression;

[tex]9^{2x-1} = 2\\[/tex]

This gives the required exponential equation

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