Answered

Get personalized answers to your specific questions with IDNLearn.com. Discover reliable and timely information on any topic from our network of experienced professionals.

In ΔFGH, the measure of ∠H=90°, FH = 8, OF = 17, and HG = 15. What ratio represents the sine of ∠G?

Sagot :

MrRoyalidn

Answer:

[tex]\sin(G) = \frac{8}{17}[/tex]

Step-by-step explanation:

Given

[tex]\angle H = 90^o[/tex]

[tex]FH = 8[/tex]

[tex]GF = 17[/tex]

[tex]HG = 15[/tex]

See attachment for illustration

Required

The ratio of [tex]\sin(G)[/tex]

[tex]\sin(G)[/tex] is calculated as:

[tex]\sin(G) = \frac{Opposite}{Hypotenuse}[/tex]

From the attachment, we have:

[tex]\sin(G) = \frac{FH}{GF}[/tex]

This gives:

[tex]\sin(G) = \frac{8}{17}[/tex]

View image MrRoyal
We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. IDNLearn.com is your source for precise answers. Thank you for visiting, and we look forward to helping you again soon.