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Let p(x)=4x-18 and q(x)=-2x+k. For what value of k will the x intercept of q(x) be equivalent to the x intercept of p(x)

Sagot :

Luv2Teachidn

Answer:

Step-by-step explanation:

The x-intercept of a line exists where y = 0. So first we will set each of those lines = 0:

4x - 18 = 0   and   -2x + k = 0. In order for the x-intercepts to be equal, we have to solve each equation for x and then set those expressions equal to each other.

4x = 18 so

x = 9/2.

-2x = -k so

x = k/2. If the x-intercepts are the same value, then

[tex]\frac{9}{2}=\frac{k}{2}[/tex] so, obviously,

k = 9

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