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Answer:
2
Step-by-step explanation:
Given the nth term equation:
C(n) = - 6(-1/3)^(n-1)
The 2nd term :
C(2) = - 6(-1/3)^(2-1)
C(2) = - 6(-1/3)^1
C(2) = - 6(-1/3)
C(2) = - 6 * - 1/3
C(2) = 2