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Sagot :
Answer:
151 g/mol
Explanation:
In order to solve this problem we need to keep in mind the formula for the boiling point elevation:
- ΔT = Kb * m * i
Where:
- ΔT is the temperature difference between the boiling point of the solution and that of pure water. 100.37 °C - 100.00 °C = 0.37 °C.
- m is the molarity of the solution
- i is the van't Hoff factor. As the solute is a nonelectrolyte, the factor is 1.
Input the data and calculate m:
- 0.37 °C = 0.51 °C/m * m * 1
- m =0.72 m
We now can calculate the number of moles of the substance, using the definition of molarity:
- molarity = moles of solute / kg of solvent
In this case kg of solvent = 90.0 g / 1000 = 0.090 kg
- 0.72 m = moles / 0.090 kg
- moles = 0.065 mol
Finally we calculate the molar mass, using the number of moles and the mass:
- 9.81 g / 0.065 mol = 151 g/mol
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