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Please I need help with this!!!!!!!

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Sagot :

Answer:

Step-by-step explanation:

1). Step 4:

   [tex]x=5^{\frac{4}{3}}=(5^4)^{\frac{1}{3}}[/tex]

   [tex]x=\sqrt[3]{5^4}[/tex] [Since, [tex]a^{\frac{1}{3}}=\sqrt[3]{a}[/tex]]

   [tex]x=\sqrt[3]{5\times 5\times 5\times 5}[/tex]

   Step 5:

   [tex]x=\sqrt[3]{(5)^3\times 5}[/tex]

   [tex]x=\sqrt[3]{5^3}\times \sqrt[3]{5}[/tex]

2). He simplified the expression by removing exponents from the given expression.

3). Let the radical equation is,

   [tex](3x-1)^{\frac{1}{5}}=2[/tex]

   Step 1:

   [tex](3x-1)^{\frac{1}{5}\times \frac{5}{1} }=2^{\frac{5}{1}}[/tex]

   Step 2:

   [tex](3x-1)=2^5[/tex]

   Step 3:

   [tex]3x=32+1[/tex]

   Step 4:

   [tex]x=11[/tex]

4). By substituting [tex]x=11[/tex] in the original equation.

   [tex](3\times 11-1)^{\frac{1}{5}}=(32)^\frac{1}{5}[/tex]

                         [tex]=(2^5)^\frac{1}{5}[/tex]

                         [tex]=2[/tex]

There is no extraneous solution.

PriyAnjaleeidn

1). Step 4:

   x=5^{\frac{4}{3}}=(5^4)^{\frac{1}{3}}x=534=(54)31

   x=\sqrt[3]{5^4}x=354 [Since, a^{\frac{1}{3}}=\sqrt[3]{a}a31=3a

   x=\sqrt[3]{5\times 5\times 5\times 5}x=35×5×5×5

   Step 5:

   x=\sqrt[3]{(5)^3\times 5}x=3(5)3×5

   x=\sqrt[3]{5^3}\times \sqrt[3]{5}x=353×35

2). He simplified the expression by removing exponents from the given expression.

3). Let the radical equation is,

   (3x-1)^{\frac{1}{5}}=2(3x−1)51=2

   Step 1:

   (3x-1)^{\frac{1}{5}\times \frac{5}{1} }=2^{\frac{5}{1}}(3x−1)51×15=215

   Step 2:

   (3x-1)=2^5(3x−1)=25

   Step 3:

   3x=32+13x=32+1

   Step 4:

   x=11x=11

4). By substituting x=11x=11 in the original equation.

   (3\times 11-1)^{\frac{1}{5}}=(32)^\frac{1}{5}(3×11−1)51=(32)51

                         =(2^5)^\frac{1}{5}=(25)51

                         =2=2

There is no extraneous solution.