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Two consecutive even numbers are such that five times the smaller number , subtracted from eight times the bigger gives 58. Find the two Numbers? show working​

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Answer:

[tex]14\text{ and }16[/tex]

Step-by-step explanation:

Let the smaller number be [tex]x[/tex]. Since they are consecutive even numbers, the larger number can be represented by [tex]x+2[/tex].

Therefore, we have the following equation:

[tex]8(x+2)-5x=58,\\8x+16-5x=58,\\3x=42,\\x=\boxed{14}[/tex]

Thus, the larger number is [tex]x+2=\boxed{16}[/tex]

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