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Given f(x) = x + 1 and g(x) = x^2, what is
( g o f) (x)?

A: ( g o f) (x) = x^2 + 1

B: ( g o f) (x) = ( x + 1)^2

C: ( g o f) (x) = x^2 + x + 1

D: ( g o f) (x) = x^2 ( x + 1)​

Sagot :

Kkozume27idn

Answer:

The answer is B: ( g o f) (x) = ( x + 1)^2

Explanation:

⟹ (g ∘ f) (x) = g [f (x)]

Replace x in g(x) = x^2 with x+1

= ( x + 1 ) ^2

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