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How to solve this?!?!? (5x+24)(9x+12) + (3x+9)(8x+6)(2x+7)

Sagot :

Renardtnt1idn

Answer and Step-by-step explanation:

First, multiply the parentheses, then add everything together.

-- (5x + 24)(9x +  12)

-- 45[tex]x^2\\[/tex] + 60x + 216x + 288 (Simplify)

-- 45[tex]x^2\\[/tex] + 276x + 288

--- (3x + 9)(8x + 6)

--- 24[tex]x^2\\[/tex] + 18x + 72x + 54 (Simplify)

--- 24[tex]x^2\\[/tex] + 90x + 54

---- (2x + 7)(24[tex]x^2\\[/tex] + 90x + 54)

---- 48[tex]x^{3}[/tex] + 180[tex]x^2\\[/tex] + 108x + 168[tex]x^2\\[/tex] + 630x + 378 (Simplify)

---- 48[tex]x^{3}[/tex] + 348[tex]x^2\\[/tex] + 738x + 378

----- 45[tex]x^2\\[/tex] + 276x + 288 + 48[tex]x^{3}[/tex] + 348[tex]x^2\\[/tex] + 738x + 378

----- 48[tex]x^{3}[/tex] + 393[tex]x^2\\[/tex] + 1014x + 666

48[tex]x^{3}[/tex] + 393[tex]x^2\\[/tex] + 1014x + 666 is the final answer.

#teamtrees #PAW (Plant And Water)

Nayefxidn

Answer:

[tex] \rm \displaystyle {48x}^{3} + 393 {x}^{2} +1014x + 660[/tex]

Step-by-step explanation:

we would like to simplify the following:

[tex] \rm \displaystyle (5x + 24)(9x + 12) + (3x + 9)(8x + 6)(2x + 7)[/tex]

there're two parts the multiplication the whole part to solve the multiplication part we can consider FOIL and for the whole, PEMDAS which can be represented as

[tex] \rm\displaystyle \rm \displaystyle \underbrace{\underbrace{(5x + 24)(9x + 12) } _{ \text{FOIL - 1}}+ \underbrace{ (3x + 9)(8x + 6)(2x + 7)} _{ \text{FOIL - 2}}} _{ \text{PEMDAS}}[/tex]

let's figure out FOIL-1 part

By FOIL we obtain:

[tex] \displaystyle {45x}^{2} + 60x + 216x + 288[/tex]

simplify addition:

[tex] \displaystyle {45x}^{2} + 276x+ 288[/tex]

let's figure out FOIL-2:

By FOIL and PEMDAS we acquire:

[tex] \rm \displaystyle {48x}^{3 } + {348x}^{2} + 738x + 378[/tex]

finally the whole part

[tex] \rm \displaystyle {45x}^{2} + 60x + 216x + 288+ {48x}^{3 } + {348x}^{2} + 738x + 378[/tex]

combine like terms:

[tex] \rm \displaystyle {48x}^{3} + 393 {x}^{2} +1014x + 660[/tex]

and we are done!

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