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Sagot :
[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \huge \mathrm{ \underbrace{Answer}}[/tex]
The given equation is :
[tex] \huge \boxed{ y = 2x + 6 }[/tex]
Now, let's solve for each value of "x"
[tex]\mathrm {\hookrightarrow \:1. \: \: when \: \: x = 0}[/tex]
- [tex]y = 2x + 6[/tex]
- [tex]y = (2 \times 0) + 6[/tex]
- [tex]y = 6[/tex]
[tex]\mathrm{\hookrightarrow 2.\: \: when \: \: x = 1}[/tex]
- [tex]y = 2x + 6[/tex]
- [tex]y = (2 \times 1) + 6[/tex]
- [tex]y = 2 + 6[/tex]
- [tex]y = 8[/tex]
[tex]\mathrm {\hookrightarrow \: 3. \: \: when \: \: x = 2}[/tex]
- [tex]y = 2x + 6[/tex]
- [tex]y = (2 \times 2) + 6[/tex]
- [tex]y = 4 + 6[/tex]
- [tex]y = 10[/tex]
[tex]\mathrm{\hookrightarrow \: 4. \: \: when \: \: x = 3}[/tex]
- [tex]y = 2x + 6[/tex]
- [tex]y = (2 \times 3) + 6[/tex]
- [tex]y = 6 + 6[/tex]
- [tex]y = 12[/tex]
[tex] \mathrm{✌TeeNForeveR✌}[/tex]
Answer:
[tex]\huge\boxed{Answer\hookleftarrow}[/tex]
Equation = [tex]\large\bold{y = 2x + 6}[/tex]
a) [tex]x = 0[/tex]
Substitute the value of x as 0 in the equation.
[tex]y = 2x + 6 \\ y = 2(0) + 6 \\ y = 0 + 6 \\ y = 6[/tex]
✐ Answer of a) is [tex]\large\bold{y = 6}[/tex]
____________________
b) [tex]x = 1[/tex]
Substitute the value of x as 1 in the equation.
[tex]y = 2x + 6 \\ y = 2(1) + 6 \\ y = 2 + 6 \\ y = 8[/tex]
✐ Answer of b) is [tex]\large\bold{y = 8}[/tex]
____________________
c) [tex]x = 2[/tex]
Substitute the value of x as 2 in the equation.
[tex]y = 2x + 6 \\ y = 2(2) + 6 \\ y = 4 + 6 \\ y = 10[/tex]
✐ Answer of b) is [tex]\large\bold{y = 10}[/tex]
____________________
d) [tex]x = 3[/tex]
Substitute the value of x as 3 in the equation.
[tex]y = 2x + 6 \\ y = 2(3) + 6 \\ y = 6 + 6 \\ y = 12[/tex]
✐ Answer of d) is [tex]\large\bold{y = 12}[/tex]
____________________
ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ
# ꧁❣ RainbowSalt2²2² ࿐
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