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Using the formula for the margin of error, it is found that a smaller confidence interval would be obtained as follow:
D. Increase the sample size to 64.
It is given by the following formula:
[tex]M = z\frac{s}{\sqrt{n}}[/tex]
In which:
For a smaller interval, we need to decrease the margin of error, which is possible increasing the sample size, hence option D is correct.
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