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PLEASE HELP WITH ALGEBRA HOMEWORK.WILL MARK BRAINLIEST

PLEASE HELP WITH ALGEBRA HOMEWORKWILL MARK BRAINLIEST class=

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Wallind123idn

[tex] {36}^{2x + 5} = {216}^{x - 1} [/tex]

[tex] {6}^{2(2x + 5)} = {6}^{3(x - 1)} [/tex]

[tex] {6}^{(4x + 10)} = {6}^{(3x - 3)} [/tex]

Since bases i.e 6 are same exponents are equal

4x+10= 3x-3

4x-3x = -3-10

x= -13

Answer:

x = -13

Step-by-step explanation:

36 = 6^2

216 = 6^3

36^(2x + 5) = 6^(2)^(2x + 5)

When taking an exponent to an exponet: multiply the exponents

36^(2x + 5) = 6^(4x + 10)

216^(x - 1) = 6^(3)^(x - 1)

When taking an exponent to an exponet: multiply the exponents

216^(x - 1) = 6^(3x - 3)

-----------------------------

Therefor

6^(4x + 10) = 6^(3x - 3)

Since the bases are the same the exponents are equal

4x + 10 = 3x - 3

Subtract 3x from both sides

x + 10 = -3

subtract 10 from both sides

x = -13

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