Zymiereidn
Answered

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Find the value of x in the isosceles triangle shown below​

Find The Value Of X In The Isosceles Triangle Shown Below class=

Sagot :

Senalvidunidn

Answer:

x²+4² =8²

x²+16 =64

x² =64-16.

x² =48

x. =√48

answer is option D

Answer:

D

Step-by-step explanation:

The segment x is a perpendicular bisector and divides the triangle into 2 right triangles.

Using Pythagoras' identity in either of the 2 right triangles, then

x² + 4² = 8²

x² + 16 = 64 ( subtract 16 from both sides )

x² = 48 ( take the square root of both sides )

x = [tex]\sqrt{48}[/tex] → D

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