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11. Square ABCD shown has sides of length 10 centimeters. The unshaded
portions are both semicircles. Calculate the area of the shaded portion to
the nearest tenth of a square centimeter. *


11 Square ABCD Shown Has Sides Of Length 10 Centimeters The Unshaded Portions Are Both Semicircles Calculate The Area Of The Shaded Portion To The Nearest Tenth class=

Sagot :

Answer:

21cm^2

Step-by-step explanation:

Area of Square-Area of semi circles (makes one full circle)

Squares Area = 100

LxW or (10x10)=100

Circle Area = 25/pi

/pi (radius)^2 or /pi(5)^2 = 25/pi

100cm^2-25cm^2 = 21.4601…cm^2 rounded to 21.5 cm^2

The area of the shaded region is 21.5 cm²

What is a semi-circle?

'In geometry, a semicircle is a plane figure that is formed by dividing a circle into exactly two parts.'

According to the given problem,

Side length of the square = 10

Area of the square = ( 10 × 10 )

                               = 100 cm²

Now, for the semi-circle,

Diameter = 10 cm

Radius = [tex](\frac{10}{2}[/tex][tex])[/tex] cm

            = 5 cm

Area of the semicircle =  [tex]\frac{\pi r^{2} }{2}[/tex]

                                     = [tex]\frac{\pi * 5^{2} }{2}[/tex]

Since, there are two semicircles in the square, we multiply the area with 2,

⇒ [tex]\frac{\pi *5^{2} }{2}*2[/tex]

= 25[tex]\pi[/tex]

Area of the shaded region = ( 100 - 25π )

                                            = ( 100 - 78.53 )

                                            = 21.46

                                            ≈ 21.5 cm²

Hence, we can conclude, the area of the shaded region is 21.5 cm².

Learn more about semi-circles here: https://brainly.com/question/14429410

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