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Answered

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Find a round to the nearest tenth 12 22 75 x x=?

Find A Round To The Nearest Tenth 12 22 75 X X class=

Sagot :

Answer:

By law of Sines

[tex]\frac{Sin75^o}{22} =\frac{Sinx}{12}[/tex]

  • [tex]\frac{Sin75}{22}(12)=\frac{Sinx}{12} (12)[/tex]
  • [tex]0.5268=Sinx[/tex]
  • [tex]Sin^(0.5268)=x[/tex]
  • [tex]x=31.789[/tex]
  • [tex]x=31.79^o[/tex]

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