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Answer:
A. (-2.28, 3.38)
Step-by-step explanation:
The confidence interval of the slope :
b ± Tcritical*SE
Tcritical at 95%, df = n - 2 = (15 - 2) = 13
Tcritical = 2.160369
b = slope Coefficient = 0.54924
S.E = 1.311
Hence, we have :
Confidence interval = 0.54924 ± (2.160369 * 1.311)
Confidence interval = 0.54924 ± 2.832243759
Lower boundary = 0.54924 - 2.83224 = - 2.283
Upper boundary = 0.54924 + 2.83224 = 3.3814
The answer option is A. (-2.28, 3.38)