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Write an exponential function in the form y=ab^x that goes through the point (0,17) and (6,1088)

Sagot :

Altavistardidn

Answer:

y = 17(2)^x

Step-by-step explanation:

If the graph of y = ab^x goes through (0, 17), then

                        17 = ab*0, or a = 17

Then the function is y = ab^x with a = 17, or

                                  y = 17*b^x and we must find b.

If the graph of y = 17*b^x also goes through (6, 1088), then the following must be true:   1088 = 17*b^6

which reduces to 64 = b^6

Taking the sixth root of both sides, we get 64^(1/6) = b, and so b = 2

Then the desired exponential function is

y = 17(2)^x

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