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Write an equation of a line in slope-intercept form with a slope of -12 and a y-intercept of 3.
a
y = 3x - 12
y = -12(3)+b
Ob
Ос
3= -12x + b
Od
y=-12x + 3

Write An Equation Of A Line In Slopeintercept Form With A Slope Of 12 And A Yintercept Of 3 A Y 3x 12 Y 123b Ob Ос 3 12x B Od Y12x 3 class=

Sagot :

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Answer:

y = -12x + 3

Step-by-step explanation:

The slope-intercept form of an equation can be written as y = mx + b where m is the slope and b is the y-intercept. We are given both values, so we can plug them into the equation to get:

y = mx + b

y = -12x + 3

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