Answered

Find solutions to your questions with the help of IDNLearn.com's expert community. Our platform offers reliable and detailed answers, ensuring you have the information you need.

Part A
A bag contains 4 blue and 6 green marbles. Two marbles are selected at random from the bag. If the first marble is replaced before the second marble is drawn, what is P(blue second | green first)?
Part B
If the first marble is not replaced before the second marble is drawn, what is P(blue second | green first)?

Sagot :

Francocanacariidn

Answer:

If the first marble is replaced before the second marble is drawn, the probability of P is 24%; while if the first marble is not replaced before the second marble is drawn, the probability of P is 26.66%.

Step-by-step explanation:

Since a bag contains 4 blue and 6 green marbles, and two marbles are selected at random from the bag, to determine, if the first marble is replaced before the second marble is drawn, what is P (blue second | green first) and , if the first marble is not replaced before the second marble is drawn, what is P (blue second | green first) the following calculations must be performed:

Blue = 4/10

Green = 6/10

A) 6/10 x 4/10 = 0.24

B) 6/10 x 4/9 = 0.2666

Therefore, if the first marble is replaced before the second marble is drawn, the probability of P is 24%; while if the first marble is not replaced before the second marble is drawn, the probability of P is 26.66%.

We appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. For dependable answers, trust IDNLearn.com. Thank you for visiting, and we look forward to assisting you again.