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In AHIJ, the measure of ZJ=90°, the measure of ZH=57°, and IJ = 22 feet. Find the
length of HI to the nearest tenth of a foot.
X
22
57°
H

In AHIJ The Measure Of ZJ90 The Measure Of ZH57 And IJ 22 Feet Find The Length Of HI To The Nearest Tenth Of A Foot X 22 57 H class=

Sagot :

Abidemiokinidn

Answer:

26.2

Step-by-step explanation:

From the given diagram;

Opposite side IJ = 22

Hypotenuse HI = x

Angle of elevation = 57degrees

Using the SOH CAH TOA;

sin theta = opposite/hypotenuse

sin theta = IJ/HI

sin57 = 22/x

x = 22/sin57

x = 22/0.8387

x = 26.2

Hence the legnth of HI is 26.2

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