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Answer:
[tex]2360m^2[/tex] of sheet steel are needed
Step-by-step explanation:
Given
The missing dimensions are:
[tex]Length = 5m[/tex]
[tex]Width = 6m[/tex]
[tex]Height = 8m[/tex]
[tex]n=10[/tex] --- number of containers
Required
The surface area of all containers
First, we calculate the surface area (A) of 1 container
[tex]A=2*(Length * Width + Length * Height + Width * Height)[/tex]
[tex]A=2*(5m* 6m+ 5m* 8m+ 6m * 8m)[/tex]
[tex]A=2*(30m^2 + 40m^2 + 48m^2)[/tex]
[tex]A=2*(118m^2)[/tex]
[tex]A=236m^2[/tex]
The surface area of 10 is:
[tex]Area = 10 * A[/tex]
[tex]Area = 10 * 236m^2[/tex]
[tex]Area = 2360m^2[/tex]