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solve for x
4^5x=(1/32)^1-x


Sagot :

x = -1

Step-by-step explanation:

[tex] {4}^{5x} = {2}^{2(5x)} = {2}^{10x} [/tex]

[tex] {( \frac{1}{32}) }^{(1 - x)} = {2}^{ - 5(1 - x)} = {2}^{(5x - 5)} [/tex]

or

[tex] {2}^{10x} = {2}^{(5x - 5)} [/tex]

Since both sides have the same base, we can write

10x = 5x - 5

or

5x = -5

x = -1

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