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write the equation of a circle with a center at (-1, -4) that passes through the point (-1,-1)

Sagot :

Sreedevi102idn

Answer:

Equation of the circle :  

                      [tex](x+ 1)^2 + (y+4)^2 = 9[/tex]

Step-by-step explanation:

Equation of a circle with centre (a, b) and radius ,r :

[tex](x - a)^2 + (y-b)^2 = r^2[/tex] ------(1)

Here a = -1, b = -4

find radius:

Since the circle passes through (-1, -1) , the radius is the distance between the centre and the point.

[tex]distance, r = \sqrt{(-1 -(-1))^2 +(-4 -(-1))^2 }[/tex]

               [tex]= \sqrt{9} = 3[/tex]

Substitute the values in (1) :

             [tex](x - (-1))^2 + (y-(-4))^2 = 3^2\\\\(x+ 1)^2 + (y+4)^2 = 9[/tex]

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