Get clear, concise, and accurate answers to your questions on IDNLearn.com. Ask your questions and receive comprehensive and trustworthy answers from our experienced community of professionals.
Sagot :
Answer:
[tex]x = 6.99in[/tex]
Step-by-step explanation:
Given
[tex]l =2in[/tex]
[tex]Volume = 72.66in^3[/tex]
See attachment for prism
Required
Find x
The prism has a regular hexagon base
The base area is calculated as:
[tex]Base\ Area= \frac{3\sqrt 3}{2}l^2[/tex]
This gives:
[tex]Base\ Area= \frac{3\sqrt 3}{2} * 2^2[/tex]
[tex]Base\ Area= \frac{3\sqrt 3}{2} * 4[/tex]
[tex]Base\ Area= 3\sqrt 3 * 2[/tex]
[tex]Base\ Area= 6\sqrt 3[/tex]
Side x represents the height.
So, we have:
[tex]Volume = Base\ Area*x[/tex]
Make x the subject
[tex]x = \frac{Volume }{ Base\ Area}[/tex]
[tex]x = \frac{72.66in^3}{6\sqrt 3 in^2}[/tex]
[tex]x = \frac{72.66}{6\sqrt 3}in[/tex]
[tex]x = \frac{12.11}{\sqrt 3}in[/tex]
[tex]x = 6.99in[/tex] --- approximated
Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Accurate answers are just a click away at IDNLearn.com. Thanks for stopping by, and come back for more reliable solutions.