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If two points on a line are given by (-7, -1) and (-7, 12), we would say the line equation is?

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[tex] \large{ \tt{❃ \: SOLUTION}} : [/tex]

  • Remember : To find the equation of straight line passing through given points ( x₁ , y₁ ) and ( x₂ , y₂ ) , Use [tex] \tt{y - y_{1} = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}(x - x_{1}}) [/tex]

  • Let the given points ( -7 , -1 ) be ( x₁ , y₁ ) & ( -7 , 12 ) be ( x₂ , y₂ ).

[tex] \underline{ \large{\tt{❁ \: USING \: TWO - POINT \: FORM \: OF \: EQUATION \: OF \: LINE : }}}[/tex]

[tex] \boxed{ \large{ \tt{❈ \: y - y_{1} = \frac{y_{2} - y _{1}}{x_{2} - x_{1}} (x - x_{1})}}}[/tex]

[tex] \large{ \tt{↦y - ( - 1) = \frac{12 - ( - 1)}{ - 7 - ( - 7)} \{x - ( - 7) \}}} [/tex]

[tex] \large{ \tt{↦y + 1 = \frac{12 + 1}{ - 7 + 7}(x + 7)} }[/tex]

[tex] \large \tt \:↦ \: y + 1 = \frac{12}{0} (x + 7)[/tex]

[tex] \large{ \tt{↦ \: y + 1 = 12(x + 7)}}[/tex]

[tex] \large{ \tt{↦y + 1 = 12x + 96}}[/tex]

[tex] \large{ \tt{↦ \: 12x + 96 = y + 1}}[/tex]

[tex] \large{ \tt{↦ \: 12x - y + 96 - 1 = 0}}[/tex]

[tex] \large{ \boxed{ \tt↦12x - y + 95 = 0}}[/tex]

  • Hence , 12x - y + 95 = 0 is the required equation of the line.

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