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solve 3x²-2x-5=0 by factorization method​

Sagot :

Bhadelsimron19idn

Answer:

Step-by-step explanation:

3x^2 -2x -5=0

3x^2 -(5-3)x -5=0

3x^2 -5x +3x -5=0

x(3x -5)+1(3x -5)=0

(x+1)(3x-5)=0

either (x+1)=0           OR, (3x-5)=0

x+1=0

x=0-1

x=-1

3x-5=0

3x=0+5

x=5/3

x=-1, 5/3

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