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Sagot :
Answer:
Step-by-step explanation:
r = 3 km
Ф = 90°
Area of a sector = [tex]\frac{theta}{360}*\pi *r^{2}[/tex]
[tex]= \frac{90}{360}* 3.14 * 3 * 3\\\\= \frac{3.14*3*3}{4}\\[/tex]
= 7.065 sq.km
Answer:
Solution given:
r=3km
area of sector bounded by a 90° arc=90°/360°*πr²
=¼*π*3²
=9/4 π or 7.068km²
is a required answer
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