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Which equation(s) have -4 and 4 as solutions?
A. x2 = 8
B. x2 + 16 = 0
C. 2x2 = 32
D. -3x2 = -48
E. 6x2 + 56 = -40
F 27 - 5x2 = -53
C because... 2x^2 = 32 becomes... 2x^2 - 32 = 0 (FACTOR OUT THE 2!) 2(x^2 - 16) = 0 —> now we have a difference of squares 2 (x + 4) (x - 4) = 0 Our two solutions are 4 and -4.
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