Answer:
Aluminum
Explanation:
Given
[tex]T_1 = 25.2^oC[/tex]
[tex]T_2 = 55.1^oC[/tex]
[tex]m = 5.00g[/tex]
[tex]\triangle Q= 133J[/tex]
See attachment for chart
Required
Identify the unknown substance
To do this, we simply calculate the specific heat capacity from the given parameters using:
[tex]c = \frac{\triangle Q}{m\triangle T}[/tex]
This gives:
[tex]c = \frac{\triangle Q}{m(T_2 - T_1)}[/tex]
So, we have:
[tex]c = \frac{133J}{5.00g * (55.1C - 25.2C)}[/tex]
[tex]c = \frac{133J}{5.00g * 29.9C}[/tex]
[tex]c = \frac{133J}{149.5gC}[/tex]
[tex]c = 0.89\ J/gC[/tex]
From the attached chart, we have:
[tex]Al(s) = 0.89\ J/gC[/tex] --- The specific heat capacity of Aluminum
Hence, the unknown substance is Aluminum
