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find the value of x.

Find The Value Of X class=

Sagot :

Wegnerkolmp2741oidn

Answer:

x = sqrt(33)

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean theorem

a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse

4^2 + x^2 = 7^2

16 + x^2 = 49

Subtract 16 from each side

x^2 = 49-16

x^2 = 33

Take the square root of each side

sqrt(x^2) = sqrt(33)

x = sqrt(33)

Pythagorean Theorem:

[tex]\quad\quad\quad \boxed{ \tt{\color{blue}{c}^{2} = {a}^{2} + {b}^{2} }}[/tex]

To find the value of x. Let's use this formula:

[tex]\quad\quad\quad \boxed{ \tt{\color{blue}{a} = \sqrt{ {c}^{2} - {b}^{2} \: \: } }}[/tex]

Imagine that "a" is the "x".

[tex]\quad\quad\quad \boxed{ \tt{\color{black}{a} = \sqrt{ {c}^{2} - {b}^{2} \: \: } }}[/tex]

[tex]\quad\quad\quad \boxed{ \tt{{x} = \sqrt{ {c}^{2} - {b}^{2} \: \: } }}[/tex]

[tex]\quad\quad\quad \boxed{ \tt{{x} = \sqrt{ {7}^{2} - {4}^{2} \: \: } }}[/tex]

[tex]\quad\quad\quad \boxed{ \tt{{x} = \sqrt{ {49} - {16} \: \: } }}[/tex]

[tex]\quad\quad\quad \boxed{ \tt \color{black}{{x} = \sqrt{ 33} }}[/tex]

Hence, The value of x is,

[tex]\quad\quad\quad \boxed{ \tt \color{green}{{x} = \sqrt{ 33} }}[/tex]

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