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In parallelogram KLMN if m&NKL=55° find m2MNK.
L
M
к.
55°
X°N

In Parallelogram KLMN If MampNKL55 Find M2MNK L M К 55 XN class=

Sagot :

Answer:

Value of ∠N = 135°

Explanation:

Given that;

Quadrilateral KLMN is a parallelogram

Value of ∠K = 55°

Find:

Value of ∠N = x°

Computation:

We know that;

Quadrilateral KLMN is a parallelogram

We know that in a parallelogram, sum of co-interior angle is 180

So,

⇒ ∠K + ∠N = 180°

⇒ 55 + x  = 180

⇒ x = 180 - 55

⇒ x = 135

So,

⇒ Value of x = 55

Value of ∠N = 135°

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