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The bx36 bus comes every 14 minutes.the bx32 bus comes every 4 minutes.both buses arrive at 4:00pm.what time will it be when both buses arrive at the same time again?
the number of times bx36 comes is represented by x the number of times bx32 comes is represented by y
bx36 times (like 1ocloc, 2 o clock etc) it comes is 14x because if it comes once then 14 mins have passed
likewise with bx32 so 4y so we want to find when 14x=4y so we try and solve for when x and y are equal 14x=4y divide both sides by 2 7x=2y divide both sides by 2 3.5x=y subsitute a value for x will yield a whole value if we multiply .5 by 2 then it will yield a whole (nondecimal) value 3.5(2)=7 the first time is when x=2 and y=7 (followed by (x,y)(2,7)(4,14)(6,21))so if x=2 then 14x=14(2)=28 4:00+28=4:28 4:28 is the next time
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