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Evaluate the function (f/g)(-1)-g(3) for f(x)=x^2+1 and g(x)=x-4

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[tex](f/g)(-1)-g(3)=\frac{f(-1)}{g(-1)}-g(3) \\ \\ f(x)=x^2+1 \\ f(-1)=(-1)^2+1=1+1=2 \\ g(x)=x-4 \\ g(-1)=-1-4=-5 \\ g(3)=3-4=-1 \\ \\ \frac{f(-1)}{g(-1)}-g(3)=\frac{2}{-5}-(-1)=-\frac{2}{5}+1=\frac{3}{5} \\ \\ \boxed{(f/g)(-1)-g(3)=\frac{3}{5}}[/tex]
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