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How many moles of
H
C
l
are in
44.1
mL
of a
1.26
M
H
C
l
solution?

Sagot :

Answer: There are 0.0556 moles present in 44.1 mL of a 1.26 M HCl solution.

Explanation:

Given: Volume = 44.1 mL (1 mL = 0.001 L) = 0.0441 L

Molarity = 1.26 M

Molarity is the number of moles of a substance present in liter of a solution.

Therefore, moles of HCl are calculated as follows.

[tex]Moles = \frac{moles}{Volume (in L)}\\1.26 M = \frac{moles}{0.0441 L}\\moles = 0.0556 mol[/tex]

Thus, we can conclude that there are 0.0556 moles present in 44.1 mL of a 1.26 M HCl solution.

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