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Sagot :
Given:
The numbers are [tex]\dfrac{3}{5},2,0,1,-0.45, 1.44[/tex].
To find:
All the values that cannot be probabilities.
Solution:
We know that,
[tex]\text{Probability}=\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}[/tex]
The minimum value of favorable outcomes is 0 and the maximum value is equal to the total outcomes. So, the value of probability lies between 0 and 1, inclusive. It other words, the probability lies in the interval [0,1].
[tex]0\leq \text{Probability}\leq 1[/tex]
From the given values only [tex]\dfrac{3}{5}, 0, 1[/tex] lie in the interval [0,1]. So, these values can be probabilities.
The values [tex]2,-0.45, 1.44[/tex] does not lie in the interval [0,1]. So, these values cannot be probabilities.
Therefore, the correct values are [tex]2,-0.45, 1.44[/tex].
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