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A softball pitcher throws a softball to a catcher behind home plate. The softball is 3 feet above the ground when it leaves the pitcher's hand at a velocity of 50 feet per second. If the softball's acceleration is –16 ft/s2, which quadratic equation models the situation correctly?

Sagot :

MrRoyalidn

Answer:

The function is:

[tex]f(t) = -16t^2 + 50t + 3[/tex]

Step-by-step explanation:

Given

[tex]height = 3ft[/tex]

[tex]velocity = 50ft/s[/tex]

[tex]acceleration = -16ft/s^2[/tex]

Required

The function

Let t represents time;

So, we have:

[tex]f(t) = acceleration * t^2 + velocity * t + height[/tex]

So, we have:

[tex]f(t) = -16* t^2 + 50* t + 3[/tex]

[tex]f(t) = -16t^2 + 50t + 3[/tex]

Answer:

b on edge

Step-by-step explanation:

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