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Sagot :
The question is as follows: What is the% m / m of a solution in which 22 g of solute are dissolved in 44 g of solvent?
Answer: The% m/m of a solution in which 22 g of solute are dissolved in 44 g of solvent is 50%.
Explanation:
Given: Mass of solute = 22 g
Mass of solvent = 44 g
The percentage m/m is calculated using the following formula.
[tex]Mass percentage = \frac{mass of solute}{mass of solvent} \times 100[/tex]
Substitute the values into above formula as follows.
[tex]Mass percentage = \frac{mass of solute}{mass of solvent} \times 100\\= \frac{22 g}{44 g} \times 100\\= 50 percent[/tex]
Thus, we can conclude that the% m/m of a solution in which 22 g of solute are dissolved in 44 g of solvent is 50%.
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