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Answer:
The appropriate answer is "0.9803".
Step-by-step explanation:
According to the question,
The probability of sample proportion differs from population proportion by les than 4% will be:
= [tex]P(-\frac{0.04}{\sqrt{\frac{0.23\times 0.77}{602} } }<z<\frac{0.04}{\sqrt{\frac{0.23\times 0.77}{602} } } )[/tex]
= [tex]P(-\frac{0.04}{\sqrt{\frac{0.1771}{602} } }<z<\frac{0.04}{\sqrt{\frac{0.1771}{602} } } )[/tex]
= [tex]P(-2.33<z<2.33)[/tex]
= [tex]0.9803[/tex]