Mannybeava04idn
Answered

Discover new information and insights with the help of IDNLearn.com. Get accurate and timely answers to your queries from our extensive network of experienced professionals.

In basketball, hang time is the time that both of your feet are off the ground during a jump. The equation for hang time is [tex]t = 2(\frac{2h}{32} )\frac{1}2[/tex] , where t is the time in seconds, and h is the height of the jump, in feet.

Player 1 had a hang time of 0.9 s. Player 2 had a hang time of 0.8 s. To the nearest inch, how much higher did Player 1 jump than Player 2?

Sagot :

Intelligentsmartcookidn

Answer:

8 inches

Step-by-step explanation:

Given:

t = 2 ( 2h/32 ) ^1/2 ( or: t = 2 * sqrt ( 2h/32) ).

Step 1: First Player

0.9 = 2 * sqrt( 2h/32 )   / ^2 ( we will square both sides of equation )

0.81 = 4* 2h/32

0.81 = h/4

h 1 = 0.81 * 4 = 3.24 ft

Step 2: Second Player

0.8 = 2 * sqrt( 2h/32 ) /^2

0.64 = 4 * 2 h/32

h 2 = 0.64 * 4 = 2.56 ft

Step 3: Simplify

h 2 - h 1 = 3.24 - 2.56 = 0.68 ft

and since 12 in = 1 ft:

0.68 * 12 = 8.16 in ≈ 8 in.

Olivia1804idn

Answer:

The guy above me was correct. It is 8 inches!

Step-by-step explanation:

Thank you for contributing to our discussion. Don't forget to check back for new answers. Keep asking, answering, and sharing useful information. Your questions deserve precise answers. Thank you for visiting IDNLearn.com, and see you again soon for more helpful information.