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Joshua is 1.45 meters tall. At 2 p.m., he measures the length of a tree's shadow to be 31.65 meters. He stands 26.2 meters away from the tree, so that the tip of his shadow meets the tip of the tree's shadow. Find the height of the tree to the nearest hundredth of a meter .

Joshua Is 145 Meters Tall At 2 Pm He Measures The Length Of A Trees Shadow To Be 3165 Meters He Stands 262 Meters Away From The Tree So That The Tip Of His Shad class=

Sagot :

Akposevictoridn

Answer:

height of the tree ≈ 8.42 m

Step-by-step explanation:

The diagram given represents that of two similar triangles. Therefore, the corresponding lengths of the similar triangles are proportional to each other.

height of tree = h

Therefore:

1.45/h = (31.65 - 26.2)/31.65

1.45/h = 5.45/31.65

Cross multiply

h*5.45 = 1.45*31.65

h*5.45 = 45.8925

h = 45.8925/5.45

h ≈ 8.42 m (nearest hundredth)

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