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Write a program that reads a list of integers, and outputs those integers in reverse. The input begins with an integer indicating the number of integers that follow. For coding simplicity, follow each output integer by a comma, including the last one.Ex: If the input is:5 2 4 6 8 10the output is:10,8,6,4,2,To achieve the above, first read the integers into a vector. Then output the vector in reverse.

Sagot :

MrRoyalidn

Answer:

The program in C++ is as follows:

#include <iostream>

#include <vector>

using namespace std;

int main(){

   vector<int> intVect;

   int n;

   cin>>n;

int intInp;

for (int i = 0; i < n; i++) {

 cin >> intInp;

 intVect.push_back(intInp); }

for (int i = n-1; i >=0; i--) {  cout << intVect[i] << " "; }

 return 0;

}

Explanation:

This declares the vector

   vector<int> intVect;

This declares n as integer; which represents the number of inputs

   int n;

This gets input for n

   cin>>n;

This declares intInp as integer; it is used to get input to the vector

int intInp;

This iterates from 0 to n-1

for (int i = 0; i < n; i++) {

This gets each input

 cin >> intInp;

This passes the input to the vector

 intVect.push_back(intInp); }

This iterates from n - 1 to 0; i.e. in reverse and printe the vector elements in reverse

for (int i = n-1; i >=0; i--) {  cout << intVect[i] << " "; }

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