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Answer:
[tex]\frac{y^8}{x^{10}}[/tex]
Step-by-step explanation:
Given
[tex](\frac{x^{-4}y}{x^{-9}y^5})^{-2}[/tex]
Required
The equivalent
Apply law of indices to the inner bracket
[tex](x^{-4--9}y^{1 -5})^{-2}[/tex]
[tex](x^{5}y^{-4})^{-2}[/tex]
Rewrite as:
[tex]\frac{1}{(x^{5}y^{-4})^2}[/tex]
Expand
[tex]\frac{1}{(x^{5*2}y^{-4*2})}[/tex]
[tex]\frac{1}{(x^{10}y^{-8})}[/tex]
Apply law of indices
[tex]\frac{y^8}{x^{10}}[/tex]